5x^(2/3)-19x^(1/3)-4=0

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Solution for 5x^(2/3)-19x^(1/3)-4=0 equation: 


x in (-oo:+oo)

5*x^(2/3)-(19*x^(1/3))-4 = 0

5*x^(2/3)-19*x^(1/3)-4 = 0

t_1 = x^(1/3)

5*t_1^2-19*t_1^1-4 = 0

5*t_1^2-19*t_1-4 = 0

DELTA = (-19)^2-(-4*4*5)

DELTA = 441

DELTA > 0

t_1 = (441^(1/2)+19)/(2*5) or t_1 = (19-441^(1/2))/(2*5)

t_1 = 4 or t_1 = -1/5

t_1 = -1/5

x^(1/3)+1/5 = 0

1*x^(1/3) = -1/5 // : 1

x^(1/3) = -1/5

( -1/5 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 4

x^(1/3)-4 = 0

1*x^(1/3) = 4 // : 1

x^(1/3) = 4

x^(1/3) = 4 // ^ 3

x = 64

x = 64

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